VAPOR PRESSURE AND INTERMOLECULAR FORCES
In our experiment we used propionic acid (C3H6O2) with a boiling point of 372 K
INTRODUCTION
- Materials:
1. Rubber band, Schlenk tube, Stop cock (for the schlenk tube preparation)
2. Bunsen burner (to alter the temperature)
3. Vacuum maker (this will help us only the gas)
4. Gas pressure sensor (to measure the pressure)
5. Adaptor (computer and sensor)
6. Bath (to test temperature)
7. Logger pro (measurement programme)
- Procedure:
1. First, make a perfect schlenk tube, introduce the stop cock in the schlenk tube, put vaseline over it without covering the holes, press it all with the
rubber band.The air can only pass through the small tube in the left top part.
2. Then use the vacuum maker in the schlenk tube so that there is no air or particle inside.
3. Use the gas pressure sensor to measure the pressure inside the schlenk tube.
4. To measure this we should connect the gas pressure sensor to a computer using the adaptor.
5. Open in your compute the logger-pro, then it should make a graph depending on the different temperatures you apply to the schlenk tube.
6. Introduce the schlenk tube in different baths so that it is exposed to extreme temperatures and the results are shown in the graph done in the logger-pro.
7. Once you’ve finished with the graph, make a table, some conclusions and a complete lab session.
8. Be careful when you separate the different parts of the schlenk tube, the pressure and the vacuum might have join them very strongly and they can broke down.
- Table:
Name of compound
|
Molecular formula
|
Diagram of structure
|
Boiling point (oC)
|
Temperatures when vapour pressure measured (oC)
|
Vapour pressure (kPa)
|
Types of intermolecular forces
|
Butan-1-ol
|
C4H10O
| * |
987
|
0
22
34
40
|
5.6
20.3
45.6
59.1
|
Van der waals, dipole dipole, hydrogen bonding
|
Butyl acetate
|
C6H12O2
| * |
20
|
0
15
20
40
|
35,31
32,26
29,41
26,69
|
Van der waals, dipole dipole, hydrogen bonding
|
Diethyl ether
|
(C2H5)2C
| * |
34,6
|
20
25
30
35
|
38,2
44,3
64,5
102,2
|
Van der waals, dipole dipole
|
Propyl acetate
|
C5H10O2
| * |
102
|
0
15
20
40
|
4,33
7,83
9,22
10,07
|
Van der waals, dipole dipole, hydrogen bonding
|
Ethyl acetate
|
C4H8O2
| * |
77,1
|
0
15
25
40
|
9,46
12,18
14,41
20,07
|
Van der waals, dipole dipole
|
2-propanol
|
C3H8O
| * |
82,5
|
0
15
29
40
|
0,53
1,84
3,50
9,82
|
Van der waals, dipole dipole
|
pentane
|
C5H12
| * |
309,2
|
0
15
24
35
|
71,42
98,63
101,93
104,94
|
Van der waals, dipole dipole
|
Methyl acetate
|
C3H6O2
| * |
-98
|
0
15
25
35
|
0,89
9,39
20,59
21,93
|
Van der waals, hydrogen bonding, dipole dipole
|
- Results:
- Conclusion:
The main reason for this to happen are the Van der Waals force which interact in the substance caused by the induced dipole of the carbon-hydrogen bonding, the table show us how the organic particles which reacts with hydrogen particles have a high BP, while the substances which have a difference between the lone pairs of oxygen particles with the hydrogen particles have a low BP.
- References:
Canning, O. (2014). [online] Retrieved from: http://mrcanning10c.wikispaces.com/Topic+3+-+Intermolecular+forces [Accessed: 25 Feb 2014].
Summative:
ResponderEliminarB - 4 Most of the information is clearly presented but you have little detail on how the boiling point of each chemical is related to the intermlecular forces.
E - 5 The data has been processed correctly and presented clearly. Remember to title your graph and explain each axis.